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-x^2+5x+24=2x-64
We move all terms to the left:
-x^2+5x+24-(2x-64)=0
We add all the numbers together, and all the variables
-1x^2+5x-(2x-64)+24=0
We get rid of parentheses
-1x^2+5x-2x+64+24=0
We add all the numbers together, and all the variables
-1x^2+3x+88=0
a = -1; b = 3; c = +88;
Δ = b2-4ac
Δ = 32-4·(-1)·88
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-19}{2*-1}=\frac{-22}{-2} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+19}{2*-1}=\frac{16}{-2} =-8 $
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